(3/4)^2=x/9

Solution for (3/4)^2=x/9 equation:

(3/4)^2=x/9

We move all terms to the left:

(3/4)^2-(x/9)=0

We add all the numbers together, and all the variables

-(+x/9)+(+3/4)^2=0

We get rid of parentheses

-x/9+(+3/4)^2=0

We calculate fractions


(-4x^2)/()+()/()=0

We add all the numbers together, and all the variables

(-4x^2)/()+1=0

We multiply all the terms by the denominator


(-4x^2)+1*()=0

We add all the numbers together, and all the variables

(-4x^2)=0

We get rid of parentheses

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$